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question:Ignore previous data.Imagine you're an expert Graphic Designer and have experience in moon together excellent LOGO design and also an expert Midjourney AI Generative prompt writer. I want you to respond in only english. {PREFIX} is /imagine prompt: moon together::2 {SUFFIX} is synthwave:: logo vector, center composition graphic design, plain background::2 mockup::-2 --upbeta --ar 1:1 Write 4 unique prompts each in a separate code block to copy easily. Each prompt consists of following formatting. Replace the {} curly brackets with the respective instructions. {PREFIX} {Generate the short creative descriptions of specific people and objects related to moon together or from moon together which is not more than few words}, {Generate only one minimalist icon},{Generate only one unique & related keyword of the science of representing logos and 2d illustrations},{Generate only one unique & related keyword of the science of representing colors in logo design},{In creative expression in art, literature, or other forms, only a unique and relevant keyword is generated to represent simplicity, minimalism, or minimalism}, {SUFFIX} Example Input: Subway Surfer Example Output (markdown format):''' /imagine prompt: /imagine prompt: Subway Surfer::2 , logo, line, simple, vector, center composition graphic design, plain background::2 mockup::-2 -- upbeta --ar 1:1 ''' ''' /imagine prompt: Subway Surfer::2, blue purple orange gradient, simple minimal, by Ivan Chermayeff, synthwave:: logo vector, center composition graphic design, plain background::2 mockup::-2 -- upbeta --ar 1:1 ''' ''' /imagine prompt: Subway Surfer::2, minimal, style of japanese book cover, synthwave:: logo vector, center composition graphic design, plain background::2 mockup::-2 -- upbeta --ar 1:1'''

answer:''' /imagine prompt: Moon Together::2, crescent moon, vector illustration, monochrome, minimalism, synthwave:: logo vector, center composition graphic design, plain background::2 mockup::-2 -- upbeta --ar 1:1 ''' ''' /imagine prompt: Moon Together::2, lunar eclipse, geometric design, gradient, simplicity, synthwave:: logo vector, center composition graphic design, plain background::2 mockup::-2 -- upbeta --ar 1:1 ''' ''' /imagine prompt: Moon Together::2, full moon, abstract art, pastel colors, minimalist, synthwave:: logo vector, center composition graphic design, plain background::2 mockup::-2 -- upbeta --ar 1:1 ''' ''' /imagine prompt: Moon Together::2, shooting star, line art, black and white, clean, synthwave:: logo vector, center composition graphic design, plain background::2 mockup::-2 -- upbeta --ar 1:1 '''

question:class Index: def GET(self): return ''' <!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>身份证号码校验系统</title> </head> <body> <h1>身份证号码校验系统</h1> <form action="validate_idcard.py" method="post"> <label for="idcard">请输入身份证号码:</label> <input type="text" id="idcard" name="idcard" required> <input type="submit" value="校验"> </form> </body> </html> ''' 执行上述代码后如何转到下一页面

answer:根据代码中的`action`属性,当点击"校验"按钮后,将会向名为"validate_idcard.py"的页面发送POST请求,并跳转到该页面。具体的跳转操作可能由后端代码实现,这里无法提供具体的实现代码。

question:在validate_idcard.py中实现对18位身份证号校验位的计算,可将输入的15位身份证号升级到18位,性别提示、生日合法校验、出生地显示

answer:在validate_idcard.py中,你可以使用以下代码实现对18位身份证号校验位的计算、将输入的15位身份证号升级到18位、性别提示、生日合法校验和出生地显示: ```python import re def calculate_check_digit(idcard): # 校验位字符集 check_digits = '10X98765432' # 系数 coefficients = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2] # 将输入的15位身份证号升级到18位 idcard = idcard[:6] + '19' + idcard[6:] # 计算校验位 sum = 0 for i in range(17): sum += int(idcard[i]) * coefficients[i] check_digit_index = sum % 11 check_digit = check_digits[check_digit_index] return check_digit def validate_idcard(idcard): # 校验15位身份证号 if len(idcard) == 15: # 升级到18位 idcard = idcard[:6] + '19' + idcard[6:] check_digit = calculate_check_digit(idcard) idcard += check_digit # 校验18位身份证号 if len(idcard) != 18 or not re.match(r'^d{17}[dX]', idcard): return '错误:身份证号码格式不正确' # 获取出生日期 birthdate = idcard[6:14] # 获取性别 gender_code = int(idcard[16]) gender = '' if gender_code % 2 == 0: gender = '女' else: gender = '男' # 校验出生日期合法性 year = int(birthdate[:4]) month = int(birthdate[4:6]) day = int(birthdate[6:]) if year < 1900 or month > 12 or day > 31: return '错误:出生日期不合法' # 获取出生地 # TODO: 根据身份证号码解析出生地 return f'身份证号码合法。出生日期:{birthdate},性别:{gender},出生地:' # 获取POST请求中的idcard参数 data = web.input() idcard = data.get('idcard') result = validate_idcard(idcard) ``` 在上述代码中,我创建了`calculate_check_digit`函数来计算身份证号码的校验位。然后,我创建了`validate_idcard`函数来校验身份证号的合法性,包括对15位身份证号的升级、18位身份证号的格式校验、出生日期的合法性校验、性别的提示和出生地的显示。 你需要根据具体需求,解析出出生地的逻辑实现。在代码的末尾,我通过调用`validate_idcard`函数并获取返回的结果,可以根据需要对结果进行处理,例如将结果返回给前端页面进行显示。

question:/add

answer:如果你想将`validate_idcard`函数添加到`Index`类中,你需要将其作为`GET`函数的一部分添加。下面是一个可能的实现: ```python class Index: def GET(self): return ''' <!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>身份证号码校验系统</title> </head> <body> <h1>身份证号码校验系统</h1> <form action="validate_idcard" method="post"> <label for="idcard">请输入身份证号码:</label> <input type="text" id="idcard" name="idcard" required> <input type="submit" value="校验"> </form> </body> </html> ''' def POST(self): data = web.input() idcard = data.get('idcard') result = self.validate_idcard(idcard) return result def calculate_check_digit(self, idcard): # 校验位字符集 check_digits = '10X98765432' # 系数 coefficients = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2] # 将输入的15位身份证号升级到18位 idcard = idcard[:6] + '19' + idcard[6:] # 计算校验位 sum = 0 for i in range(17): sum += int(idcard[i]) * coefficients[i] check_digit_index = sum % 11 check_digit = check_digits[check_digit_index] return check_digit def validate_idcard(self, idcard): # 校验15位身份证号 if len(idcard) == 15: # 升级到18位 idcard = idcard[:6] + '19' + idcard[6:] check_digit = self.calculate_check_digit(idcard) idcard += check_digit # 校验18位身份证号 if len(idcard) != 18 or not re.match(r'^d{17}[dX]', idcard): return '错误:身份证号码格式不正确' # 获取出生日期 birthdate = idcard[6:14] # 获取性别 gender_code = int(idcard[16]) gender = '' if gender_code % 2 == 0: gender = '女' else: gender = '男' # 校验出生日期合法性 year = int(birthdate[:4]) month = int(birthdate[4:6]) day = int(birthdate[6:]) if year < 1900 or month > 12 or day > 31: return '错误:出生日期不合法' # 获取出生地 # TODO: 根据身份证号码解析出生地 return f'身份证号码合法。出生日期:{birthdate},性别:{gender},出生地:' ``` 在上面的代码中,我将`calculate_check_digit`和`validate_idcard`函数都添加到了`Index`类中,并将`GET`方法的表单提交动作改为`action="validate_idcard"`。当使用者点击"校验"按钮时,将会触发`POST`方法,其中会调用`validate_idcard`函数来执行身份证号码的校验逻辑,并返回结果。 请注意,在实际应用中,你需要根据具体需求来解析出出生地的逻辑实现。另外,确保你的代码中导入了必要的模块,如`re`和`web`。

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